4971313511 has 2 divisors, whose sum is σ = 4971313512. Its totient is φ = 4971313510.

The previous prime is 4971313483. The next prime is 4971313513. The reversal of 4971313511 is 1153131794.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4971313511 - 2⁶ = 4971313447 is a prime.

It is a super-2 number, since 2×4971313511² = 49427916049302294242, which contains 22 as substring.

Together with 4971313513, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4971313513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485656755 + 2485656756.

It is an arithmetic number, because the mean of its divisors is an integer number (2485656756).

Almost surely, 2^4971313511 is an apocalyptic number.

4971313511 is a deficient number, since it is larger than the sum of its proper divisors (1).

4971313511 is an equidigital number, since it uses as much as digits as its factorization.

4971313511 is an evil number, because the sum of its binary digits is even.

The product of its digits is 11340, while the sum is 35.

The square root of 4971313511 is about 70507.5422277645. The cubic root of 4971313511 is about 1706.6994588570.

The spelling of 4971313511 in words is "four billion, nine hundred seventy-one million, three hundred thirteen thousand, five hundred eleven".