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4971344830183 is a prime number
BaseRepresentation
bin100100001010111101100…
…1111100001111011100111
3122121020220120100200020101
41020111323033201323213
51122422303234031213
614323445420444531
71022111362560034
oct110257317417347
918536816320211
104971344830183
111647376610336
126835913a9747
132a0a46502394
14132885bac38b
15894b1be0bdd
hex4857b3e1ee7

4971344830183 has 2 divisors, whose sum is σ = 4971344830184. Its totient is φ = 4971344830182.

The previous prime is 4971344830169. The next prime is 4971344830211. The reversal of 4971344830183 is 3810384431794.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-4971344830183 is a prime.

It is a super-2 number, since 2×49713448301832 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4971344833183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485672415091 + 2485672415092.

It is an arithmetic number, because the mean of its divisors is an integer number (2485672415092).

Almost surely, 24971344830183 is an apocalyptic number.

4971344830183 is a deficient number, since it is larger than the sum of its proper divisors (1).

4971344830183 is an equidigital number, since it uses as much as digits as its factorization.

4971344830183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6967296, while the sum is 55.

The spelling of 4971344830183 in words is "four trillion, nine hundred seventy-one billion, three hundred forty-four million, eight hundred thirty thousand, one hundred eighty-three".