Base | Representation |
---|---|
bin | 100100001011000100001… |
… | …1011001001101110110001 |
3 | 122121021110222111021120022 |
4 | 1020112020123021232301 |
5 | 1122423231342334333 |
6 | 14323523400453225 |
7 | 1022120016404312 |
oct | 110261033115661 |
9 | 18537428437508 |
10 | 4971565980593 |
11 | 164747a429973 |
12 | 68363347a215 |
13 | 2a0a80283604 |
14 | 1328a72d8609 |
15 | 894c6326c98 |
hex | 485886c9bb1 |
4971565980593 has 2 divisors, whose sum is σ = 4971565980594. Its totient is φ = 4971565980592.
The previous prime is 4971565980569. The next prime is 4971565980649. The reversal of 4971565980593 is 3950895651794.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3200782199329 + 1770783781264 = 1789073^2 + 1330708^2 .
It is a cyclic number.
It is not a de Polignac number, because 4971565980593 - 224 = 4971549203377 is a prime.
It is not a weakly prime, because it can be changed into another prime (4971565980533) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485782990296 + 2485782990297.
It is an arithmetic number, because the mean of its divisors is an integer number (2485782990297).
Almost surely, 24971565980593 is an apocalyptic number.
It is an amenable number.
4971565980593 is a deficient number, since it is larger than the sum of its proper divisors (1).
4971565980593 is an equidigital number, since it uses as much as digits as its factorization.
4971565980593 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 367416000, while the sum is 71.
The spelling of 4971565980593 in words is "four trillion, nine hundred seventy-one billion, five hundred sixty-five million, nine hundred eighty thousand, five hundred ninety-three".
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