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4971565980649 is a prime number
BaseRepresentation
bin100100001011000100001…
…1011001001101111101001
3122121021110222111021122101
41020112020123021233221
51122423231342340044
614323523400453401
71022120016404422
oct110261033115751
918537428437571
104971565980649
11164747a429a14
1268363347a261
132a0a80283648
141328a72d8649
15894c6326cd4
hex485886c9be9

4971565980649 has 2 divisors, whose sum is σ = 4971565980650. Its totient is φ = 4971565980648.

The previous prime is 4971565980593. The next prime is 4971565980659. The reversal of 4971565980649 is 9460895651794.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3342095859600 + 1629470121049 = 1828140^2 + 1276507^2 .

It is a cyclic number.

It is not a de Polignac number, because 4971565980649 - 29 = 4971565980137 is a prime.

It is a super-2 number, since 2×49715659806492 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (4971565980659) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485782990324 + 2485782990325.

It is an arithmetic number, because the mean of its divisors is an integer number (2485782990325).

Almost surely, 24971565980649 is an apocalyptic number.

It is an amenable number.

4971565980649 is a deficient number, since it is larger than the sum of its proper divisors (1).

4971565980649 is an equidigital number, since it uses as much as digits as its factorization.

4971565980649 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 587865600, while the sum is 73.

The spelling of 4971565980649 in words is "four trillion, nine hundred seventy-one billion, five hundred sixty-five million, nine hundred eighty thousand, six hundred forty-nine".