Base | Representation |
---|---|
bin | 100100001011000100001… |
… | …1011001001101111101001 |
3 | 122121021110222111021122101 |
4 | 1020112020123021233221 |
5 | 1122423231342340044 |
6 | 14323523400453401 |
7 | 1022120016404422 |
oct | 110261033115751 |
9 | 18537428437571 |
10 | 4971565980649 |
11 | 164747a429a14 |
12 | 68363347a261 |
13 | 2a0a80283648 |
14 | 1328a72d8649 |
15 | 894c6326cd4 |
hex | 485886c9be9 |
4971565980649 has 2 divisors, whose sum is σ = 4971565980650. Its totient is φ = 4971565980648.
The previous prime is 4971565980593. The next prime is 4971565980659. The reversal of 4971565980649 is 9460895651794.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3342095859600 + 1629470121049 = 1828140^2 + 1276507^2 .
It is a cyclic number.
It is not a de Polignac number, because 4971565980649 - 29 = 4971565980137 is a prime.
It is a super-2 number, since 2×49715659806492 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4971565980659) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2485782990324 + 2485782990325.
It is an arithmetic number, because the mean of its divisors is an integer number (2485782990325).
Almost surely, 24971565980649 is an apocalyptic number.
It is an amenable number.
4971565980649 is a deficient number, since it is larger than the sum of its proper divisors (1).
4971565980649 is an equidigital number, since it uses as much as digits as its factorization.
4971565980649 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 587865600, while the sum is 73.
The spelling of 4971565980649 in words is "four trillion, nine hundred seventy-one billion, five hundred sixty-five million, nine hundred eighty thousand, six hundred forty-nine".
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