Base | Representation |
---|---|
bin | 1001010000110011… |
… | …11110011000110101 |
3 | 110211120022201110001 |
4 | 10220121332120311 |
5 | 40141023140302 |
6 | 2141241431301 |
7 | 234142440625 |
oct | 45031763065 |
9 | 13746281401 |
10 | 4972865077 |
11 | 2122064154 |
12 | b6949b531 |
13 | 61334aa1b |
14 | 35263a885 |
15 | 1e1896787 |
hex | 12867e635 |
4972865077 has 2 divisors, whose sum is σ = 4972865078. Its totient is φ = 4972865076.
The previous prime is 4972865069. The next prime is 4972865101. The reversal of 4972865077 is 7705682794.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4532117041 + 440748036 = 67321^2 + 20994^2 .
It is a cyclic number.
It is not a de Polignac number, because 4972865077 - 23 = 4972865069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4972865057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2486432538 + 2486432539.
It is an arithmetic number, because the mean of its divisors is an integer number (2486432539).
Almost surely, 24972865077 is an apocalyptic number.
It is an amenable number.
4972865077 is a deficient number, since it is larger than the sum of its proper divisors (1).
4972865077 is an equidigital number, since it uses as much as digits as its factorization.
4972865077 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5927040, while the sum is 55.
The square root of 4972865077 is about 70518.5442064710. The cubic root of 4972865077 is about 1706.8769962023.
The spelling of 4972865077 in words is "four billion, nine hundred seventy-two million, eight hundred sixty-five thousand, seventy-seven".
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