Base | Representation |
---|---|
bin | 1001010000110101… |
… | …01111111101000001 |
3 | 110211120201000221022 |
4 | 10220122233331001 |
5 | 40141101134342 |
6 | 2141250035225 |
7 | 234144244544 |
oct | 45032577501 |
9 | 13746630838 |
10 | 4973068097 |
11 | 2122192738 |
12 | b69578b15 |
13 | 6133bc25a |
14 | 35269085b |
15 | 1e18d69d2 |
hex | 1286aff41 |
4973068097 has 2 divisors, whose sum is σ = 4973068098. Its totient is φ = 4973068096.
The previous prime is 4973068057. The next prime is 4973068129. The reversal of 4973068097 is 7908603794.
4973068097 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3856906816 + 1116161281 = 62104^2 + 33409^2 .
It is a cyclic number.
It is not a de Polignac number, because 4973068097 - 26 = 4973068033 is a prime.
It is not a weakly prime, because it can be changed into another prime (4973068057) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2486534048 + 2486534049.
It is an arithmetic number, because the mean of its divisors is an integer number (2486534049).
Almost surely, 24973068097 is an apocalyptic number.
It is an amenable number.
4973068097 is a deficient number, since it is larger than the sum of its proper divisors (1).
4973068097 is an equidigital number, since it uses as much as digits as its factorization.
4973068097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2286144, while the sum is 53.
The square root of 4973068097 is about 70519.9836712970. The cubic root of 4973068097 is about 1706.9002239558.
The spelling of 4973068097 in words is "four billion, nine hundred seventy-three million, sixty-eight thousand, ninety-seven".
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