Base | Representation |
---|---|
bin | 101110010101101011… |
… | …010010001001100011 |
3 | 11202102120022010012001 |
4 | 232111223102021203 |
5 | 1303344440320341 |
6 | 34505115144431 |
7 | 3410665152664 |
oct | 562553221143 |
9 | 152376263161 |
10 | 49755791971 |
11 | 1a112935a36 |
12 | 9787145117 |
13 | 48cc2a7732 |
14 | 25a012136b |
15 | 1463206d31 |
hex | b95ad2263 |
49755791971 has 2 divisors, whose sum is σ = 49755791972. Its totient is φ = 49755791970.
The previous prime is 49755791909. The next prime is 49755791977. The reversal of 49755791971 is 17919755794.
49755791971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49755791971 - 215 = 49755759203 is a prime.
It is a super-2 number, since 2×497557919712 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (49755791977) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24877895985 + 24877895986.
It is an arithmetic number, because the mean of its divisors is an integer number (24877895986).
Almost surely, 249755791971 is an apocalyptic number.
49755791971 is a deficient number, since it is larger than the sum of its proper divisors (1).
49755791971 is an equidigital number, since it uses as much as digits as its factorization.
49755791971 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25004700, while the sum is 64.
The spelling of 49755791971 in words is "forty-nine billion, seven hundred fifty-five million, seven hundred ninety-one thousand, nine hundred seventy-one".
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