Base | Representation |
---|---|
bin | 100100001101000010001… |
… | …1010001110001111100001 |
3 | 122121200101121111100210001 |
4 | 1020122010122032033201 |
5 | 1123010411130022421 |
6 | 14325503101140001 |
7 | 1022326542500641 |
oct | 110320432161741 |
9 | 18550347440701 |
10 | 4975793595361 |
11 | 1649249847476 |
12 | 68441325a601 |
13 | 2a12a50aa704 |
14 | 132b8897c521 |
15 | 8967255d691 |
hex | 4868468e3e1 |
4975793595361 has 2 divisors, whose sum is σ = 4975793595362. Its totient is φ = 4975793595360.
The previous prime is 4975793595323. The next prime is 4975793595457. The reversal of 4975793595361 is 1635953975794.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4645507758336 + 330285837025 = 2155344^2 + 574705^2 .
It is a cyclic number.
It is not a de Polignac number, because 4975793595361 - 27 = 4975793595233 is a prime.
It is not a weakly prime, because it can be changed into another prime (4975793592361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2487896797680 + 2487896797681.
It is an arithmetic number, because the mean of its divisors is an integer number (2487896797681).
Almost surely, 24975793595361 is an apocalyptic number.
It is an amenable number.
4975793595361 is a deficient number, since it is larger than the sum of its proper divisors (1).
4975793595361 is an equidigital number, since it uses as much as digits as its factorization.
4975793595361 is an evil number, because the sum of its binary digits is even.
The product of its digits is 964467000, while the sum is 73.
The spelling of 4975793595361 in words is "four trillion, nine hundred seventy-five billion, seven hundred ninety-three million, five hundred ninety-five thousand, three hundred sixty-one".
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