Base | Representation |
---|---|
bin | 1110011111001100110… |
… | …11010000001011110111 |
3 | 1202120212122022220222021 |
4 | 13033212123100023313 |
5 | 31123432002033103 |
6 | 1020402534014011 |
7 | 50651425621051 |
oct | 7174633201367 |
9 | 1676778286867 |
10 | 497787142903 |
11 | 182123957186 |
12 | 80583aa7307 |
13 | 37c3086728b |
14 | 1a14339a8d1 |
15 | ce36726bbd |
hex | 73e66d02f7 |
497787142903 has 2 divisors, whose sum is σ = 497787142904. Its totient is φ = 497787142902.
The previous prime is 497787142841. The next prime is 497787142939. The reversal of 497787142903 is 309241787794.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 497787142903 - 213 = 497787134711 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (497787142943) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248893571451 + 248893571452.
It is an arithmetic number, because the mean of its divisors is an integer number (248893571452).
Almost surely, 2497787142903 is an apocalyptic number.
497787142903 is a deficient number, since it is larger than the sum of its proper divisors (1).
497787142903 is an equidigital number, since it uses as much as digits as its factorization.
497787142903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 21337344, while the sum is 61.
The spelling of 497787142903 in words is "four hundred ninety-seven billion, seven hundred eighty-seven million, one hundred forty-two thousand, nine hundred three".
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