Base | Representation |
---|---|
bin | 1110011111100000110… |
… | …00110101001010110001 |
3 | 1202121022021211101010022 |
4 | 13033300120311022301 |
5 | 31124302243430423 |
6 | 1020431304213225 |
7 | 50655525354413 |
oct | 7176030651261 |
9 | 1677267741108 |
10 | 497954280113 |
11 | 1821aa233904 |
12 | 8060ba6a215 |
13 | 37c59386534 |
14 | 1a15b6669b3 |
15 | ce4623ddc8 |
hex | 73f06352b1 |
497954280113 has 2 divisors, whose sum is σ = 497954280114. Its totient is φ = 497954280112.
The previous prime is 497954280107. The next prime is 497954280121. The reversal of 497954280113 is 311082459794.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 471353648704 + 26600631409 = 686552^2 + 163097^2 .
It is a cyclic number.
It is not a de Polignac number, because 497954280113 - 224 = 497937502897 is a prime.
It is not a weakly prime, because it can be changed into another prime (497954280143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 248977140056 + 248977140057.
It is an arithmetic number, because the mean of its divisors is an integer number (248977140057).
Almost surely, 2497954280113 is an apocalyptic number.
It is an amenable number.
497954280113 is a deficient number, since it is larger than the sum of its proper divisors (1).
497954280113 is an equidigital number, since it uses as much as digits as its factorization.
497954280113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2177280, while the sum is 53.
The spelling of 497954280113 in words is "four hundred ninety-seven billion, nine hundred fifty-four million, two hundred eighty thousand, one hundred thirteen".
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