Base | Representation |
---|---|
bin | 1011110111110… |
… | …1010110010111 |
3 | 10110200220221221 |
4 | 2331331112113 |
5 | 100221442003 |
6 | 4535151211 |
7 | 1143156211 |
oct | 275752627 |
9 | 113626857 |
10 | 49796503 |
11 | 26121939 |
12 | 14815507 |
13 | a4168b3 |
14 | 68835b1 |
15 | 45897bd |
hex | 2f7d597 |
49796503 has 2 divisors, whose sum is σ = 49796504. Its totient is φ = 49796502.
The previous prime is 49796491. The next prime is 49796507. The reversal of 49796503 is 30569794.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 49796503 - 25 = 49796471 is a prime.
It is a super-2 number, since 2×497965032 = 4959383422058018, which contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 49796503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49796507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24898251 + 24898252.
It is an arithmetic number, because the mean of its divisors is an integer number (24898252).
Almost surely, 249796503 is an apocalyptic number.
49796503 is a deficient number, since it is larger than the sum of its proper divisors (1).
49796503 is an equidigital number, since it uses as much as digits as its factorization.
49796503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 204120, while the sum is 43.
The square root of 49796503 is about 7056.6637301206. The cubic root of 49796503 is about 367.9026773791.
The spelling of 49796503 in words is "forty-nine million, seven hundred ninety-six thousand, five hundred three".
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