Base | Representation |
---|---|
bin | 100100001111010010001… |
… | …0001111011000001101111 |
3 | 122122010212012100122000101 |
4 | 1020132210101323001233 |
5 | 1123100304023221321 |
6 | 14332022225411531 |
7 | 1022560326112123 |
oct | 110364421730157 |
9 | 18563765318011 |
10 | 4980623257711 |
11 | 16502a7a91262 |
12 | 685340799ba7 |
13 | 2a189486939a |
14 | 1330c617d583 |
15 | 89856569791 |
hex | 487a447b06f |
4980623257711 has 2 divisors, whose sum is σ = 4980623257712. Its totient is φ = 4980623257710.
The previous prime is 4980623257663. The next prime is 4980623257741. The reversal of 4980623257711 is 1177523260894.
4980623257711 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 4980623257711 - 215 = 4980623224943 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4980623257741) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2490311628855 + 2490311628856.
It is an arithmetic number, because the mean of its divisors is an integer number (2490311628856).
It is a 1-persistent number, because it is pandigital, but 2⋅4980623257711 = 9961246515422 is not.
Almost surely, 24980623257711 is an apocalyptic number.
4980623257711 is a deficient number, since it is larger than the sum of its proper divisors (1).
4980623257711 is an equidigital number, since it uses as much as digits as its factorization.
4980623257711 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5080320, while the sum is 55.
The spelling of 4980623257711 in words is "four trillion, nine hundred eighty billion, six hundred twenty-three million, two hundred fifty-seven thousand, seven hundred eleven".
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