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4980623257711 is a prime number
BaseRepresentation
bin100100001111010010001…
…0001111011000001101111
3122122010212012100122000101
41020132210101323001233
51123100304023221321
614332022225411531
71022560326112123
oct110364421730157
918563765318011
104980623257711
1116502a7a91262
12685340799ba7
132a189486939a
141330c617d583
1589856569791
hex487a447b06f

4980623257711 has 2 divisors, whose sum is σ = 4980623257712. Its totient is φ = 4980623257710.

The previous prime is 4980623257663. The next prime is 4980623257741. The reversal of 4980623257711 is 1177523260894.

4980623257711 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 4980623257711 - 215 = 4980623224943 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4980623257741) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2490311628855 + 2490311628856.

It is an arithmetic number, because the mean of its divisors is an integer number (2490311628856).

It is a 1-persistent number, because it is pandigital, but 2⋅4980623257711 = 9961246515422 is not.

Almost surely, 24980623257711 is an apocalyptic number.

4980623257711 is a deficient number, since it is larger than the sum of its proper divisors (1).

4980623257711 is an equidigital number, since it uses as much as digits as its factorization.

4980623257711 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5080320, while the sum is 55.

The spelling of 4980623257711 in words is "four trillion, nine hundred eighty billion, six hundred twenty-three million, two hundred fifty-seven thousand, seven hundred eleven".