Base | Representation |
---|---|
bin | 100100001111011000011… |
… | …1111101110111111101011 |
3 | 122122011102001210012220012 |
4 | 1020132300333232333223 |
5 | 1123101223131444033 |
6 | 14332055330122135 |
7 | 1022565526331561 |
oct | 110366077567753 |
9 | 18564361705805 |
10 | 4980836593643 |
11 | 16503a7452749 |
12 | 6853a012034b |
13 | 2a18c9b12771 |
14 | 133106633a31 |
15 | 8986a15a248 |
hex | 487b0feefeb |
4980836593643 has 2 divisors, whose sum is σ = 4980836593644. Its totient is φ = 4980836593642.
The previous prime is 4980836593597. The next prime is 4980836593703. The reversal of 4980836593643 is 3463956380894.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-4980836593643 is a prime.
It is a super-2 number, since 2×49808365936432 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (4980836563643) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2490418296821 + 2490418296822.
It is an arithmetic number, because the mean of its divisors is an integer number (2490418296822).
Almost surely, 24980836593643 is an apocalyptic number.
4980836593643 is a deficient number, since it is larger than the sum of its proper divisors (1).
4980836593643 is an equidigital number, since it uses as much as digits as its factorization.
4980836593643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 403107840, while the sum is 68.
The spelling of 4980836593643 in words is "four trillion, nine hundred eighty billion, eight hundred thirty-six million, five hundred ninety-three thousand, six hundred forty-three".
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