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49836544097 is a prime number
BaseRepresentation
bin101110011010011111…
…010101000001100001
311202122012020202021112
4232122133111001201
51304031123402342
634521122033105
73412665430634
oct563237250141
9152565222245
1049836544097
111a15448022a
1297aa1a8795
134912c3c262
1425aab41c1b
15146a358682
hexb9a7d5061

49836544097 has 2 divisors, whose sum is σ = 49836544098. Its totient is φ = 49836544096.

The previous prime is 49836544067. The next prime is 49836544099. The reversal of 49836544097 is 79044563894.

49836544097 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49836544081 + 16 = 223241^2 + 4^2 .

It is a cyclic number.

It is not a de Polignac number, because 49836544097 - 210 = 49836543073 is a prime.

It is a super-2 number, since 2×498365440972 (a number of 22 digits) contains 22 as substring.

Together with 49836544099, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (49836544099) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24918272048 + 24918272049.

It is an arithmetic number, because the mean of its divisors is an integer number (24918272049).

Almost surely, 249836544097 is an apocalyptic number.

It is an amenable number.

49836544097 is a deficient number, since it is larger than the sum of its proper divisors (1).

49836544097 is an equidigital number, since it uses as much as digits as its factorization.

49836544097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 26127360, while the sum is 59.

The spelling of 49836544097 in words is "forty-nine billion, eight hundred thirty-six million, five hundred forty-four thousand, ninety-seven".