Base | Representation |
---|---|
bin | 100100010000101111011… |
… | …0011100011000011110101 |
3 | 122122102221021211110002121 |
4 | 1020201132303203003311 |
5 | 1123123211133301423 |
6 | 14333300535035541 |
7 | 1023031015302004 |
oct | 110413663430365 |
9 | 18572837743077 |
10 | 4983752634613 |
11 | 1651663488465 |
12 | 685a7480bbb1 |
13 | 2a1c72cab8ac |
14 | 133301a22c3b |
15 | 8998b16745d |
hex | 4885ece30f5 |
4983752634613 has 2 divisors, whose sum is σ = 4983752634614. Its totient is φ = 4983752634612.
The previous prime is 4983752634563. The next prime is 4983752634673. The reversal of 4983752634613 is 3164362573894.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4090336361764 + 893416272849 = 2022458^2 + 945207^2 .
It is a cyclic number.
It is not a de Polignac number, because 4983752634613 - 213 = 4983752626421 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4983752634673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2491876317306 + 2491876317307.
It is an arithmetic number, because the mean of its divisors is an integer number (2491876317307).
Almost surely, 24983752634613 is an apocalyptic number.
It is an amenable number.
4983752634613 is a deficient number, since it is larger than the sum of its proper divisors (1).
4983752634613 is an equidigital number, since it uses as much as digits as its factorization.
4983752634613 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 78382080, while the sum is 61.
The spelling of 4983752634613 in words is "four trillion, nine hundred eighty-three billion, seven hundred fifty-two million, six hundred thirty-four thousand, six hundred thirteen".
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