Base | Representation |
---|---|
bin | 10110101010100000011001… |
… | …10110010000001010010111 |
3 | 20112110120012201110100100101 |
4 | 23111100030312100022113 |
5 | 23013030301102120401 |
6 | 253555421120354531 |
7 | 13332515164426012 |
oct | 1325201466201227 |
9 | 215416181410311 |
10 | 49839016051351 |
11 | 1497567629582a |
12 | 570b175775a47 |
13 | 21a6a50679227 |
14 | c44315164379 |
15 | 5b6661b12101 |
hex | 2d540cd90297 |
49839016051351 has 2 divisors, whose sum is σ = 49839016051352. Its totient is φ = 49839016051350.
The previous prime is 49839016051343. The next prime is 49839016051387. The reversal of 49839016051351 is 15315061093894.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49839016051351 - 23 = 49839016051343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 49839016051292 and 49839016051301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49839016051651) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24919508025675 + 24919508025676.
It is an arithmetic number, because the mean of its divisors is an integer number (24919508025676).
Almost surely, 249839016051351 is an apocalyptic number.
49839016051351 is a deficient number, since it is larger than the sum of its proper divisors (1).
49839016051351 is an equidigital number, since it uses as much as digits as its factorization.
49839016051351 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3499200, while the sum is 55.
The spelling of 49839016051351 in words is "forty-nine trillion, eight hundred thirty-nine billion, sixteen million, fifty-one thousand, three hundred fifty-one".
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