Base | Representation |
---|---|
bin | 10110101010100011010110… |
… | …01010100010001000000111 |
3 | 20112110201021222222022110021 |
4 | 23111101223022202020013 |
5 | 23013042021144113434 |
6 | 254000242124240011 |
7 | 13332602330410354 |
oct | 1325215312421007 |
9 | 215421258868407 |
10 | 49840598426119 |
11 | 14976308519376 |
12 | 570b5376a0007 |
13 | 21a6c43450767 |
14 | c4442538b62b |
15 | 5b67059cdcb4 |
hex | 2d546b2a2207 |
49840598426119 has 2 divisors, whose sum is σ = 49840598426120. Its totient is φ = 49840598426118.
The previous prime is 49840598426083. The next prime is 49840598426161. The reversal of 49840598426119 is 91162489504894.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49840598426119 - 225 = 49840564871687 is a prime.
It is a super-3 number, since 3×498405984261193 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (49840598426819) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24920299213059 + 24920299213060.
It is an arithmetic number, because the mean of its divisors is an integer number (24920299213060).
Almost surely, 249840598426119 is an apocalyptic number.
49840598426119 is a deficient number, since it is larger than the sum of its proper divisors (1).
49840598426119 is an equidigital number, since it uses as much as digits as its factorization.
49840598426119 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 179159040, while the sum is 70.
The spelling of 49840598426119 in words is "forty-nine trillion, eight hundred forty billion, five hundred ninety-eight million, four hundred twenty-six thousand, one hundred nineteen".
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