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49840598426119 is a prime number
BaseRepresentation
bin10110101010100011010110…
…01010100010001000000111
320112110201021222222022110021
423111101223022202020013
523013042021144113434
6254000242124240011
713332602330410354
oct1325215312421007
9215421258868407
1049840598426119
1114976308519376
12570b5376a0007
1321a6c43450767
14c4442538b62b
155b67059cdcb4
hex2d546b2a2207

49840598426119 has 2 divisors, whose sum is σ = 49840598426120. Its totient is φ = 49840598426118.

The previous prime is 49840598426083. The next prime is 49840598426161. The reversal of 49840598426119 is 91162489504894.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 49840598426119 - 225 = 49840564871687 is a prime.

It is a super-3 number, since 3×498405984261193 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (49840598426819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24920299213059 + 24920299213060.

It is an arithmetic number, because the mean of its divisors is an integer number (24920299213060).

Almost surely, 249840598426119 is an apocalyptic number.

49840598426119 is a deficient number, since it is larger than the sum of its proper divisors (1).

49840598426119 is an equidigital number, since it uses as much as digits as its factorization.

49840598426119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 179159040, while the sum is 70.

The spelling of 49840598426119 in words is "forty-nine trillion, eight hundred forty billion, five hundred ninety-eight million, four hundred twenty-six thousand, one hundred nineteen".