Base | Representation |
---|---|
bin | 100100010010000101010… |
… | …0001111111111000000001 |
3 | 122122201101002002111200001 |
4 | 1020210022201333320001 |
5 | 1123200111212341301 |
6 | 14334454454400001 |
7 | 1023162301133605 |
oct | 110441241777001 |
9 | 18581332074601 |
10 | 4986633715201 |
11 | 16529018049a6 |
12 | 686539660001 |
13 | 2a2311b56cc8 |
14 | 1334d6511505 |
15 | 89aa906ac01 |
hex | 4890a87fe01 |
4986633715201 has 2 divisors, whose sum is σ = 4986633715202. Its totient is φ = 4986633715200.
The previous prime is 4986633715177. The next prime is 4986633715229. The reversal of 4986633715201 is 1025173366894.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3572553614400 + 1414080100801 = 1890120^2 + 1189151^2 .
It is a cyclic number.
It is not a de Polignac number, because 4986633715201 - 27 = 4986633715073 is a prime.
It is not a weakly prime, because it can be changed into another prime (4986633715601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2493316857600 + 2493316857601.
It is an arithmetic number, because the mean of its divisors is an integer number (2493316857601).
It is a 1-persistent number, because it is pandigital, but 2⋅4986633715201 = 9973267430402 is not.
Almost surely, 24986633715201 is an apocalyptic number.
It is an amenable number.
4986633715201 is a deficient number, since it is larger than the sum of its proper divisors (1).
4986633715201 is an equidigital number, since it uses as much as digits as its factorization.
4986633715201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6531840, while the sum is 55.
The spelling of 4986633715201 in words is "four trillion, nine hundred eighty-six billion, six hundred thirty-three million, seven hundred fifteen thousand, two hundred one".
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