Base | Representation |
---|---|
bin | 100100010010011011010… |
… | …0100011101101110011111 |
3 | 122122210021120100200011221 |
4 | 1020210312210131232133 |
5 | 1123203114333344023 |
6 | 14335100050354211 |
7 | 1023216512200123 |
oct | 110446644355637 |
9 | 18583246320157 |
10 | 4987372559263 |
11 | 1653150875426 |
12 | 686704b8b967 |
13 | 2a23cbc46a43 |
14 | 1335666bb583 |
15 | 89aedd6285d |
hex | 4893691db9f |
4987372559263 has 2 divisors, whose sum is σ = 4987372559264. Its totient is φ = 4987372559262.
The previous prime is 4987372559249. The next prime is 4987372559341. The reversal of 4987372559263 is 3629552737894.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4987372559263 - 213 = 4987372551071 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 4987372559192 and 4987372559201.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4987372556263) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2493686279631 + 2493686279632.
It is an arithmetic number, because the mean of its divisors is an integer number (2493686279632).
Almost surely, 24987372559263 is an apocalyptic number.
4987372559263 is a deficient number, since it is larger than the sum of its proper divisors (1).
4987372559263 is an equidigital number, since it uses as much as digits as its factorization.
4987372559263 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 685843200, while the sum is 70.
The spelling of 4987372559263 in words is "four trillion, nine hundred eighty-seven billion, three hundred seventy-two million, five hundred fifty-nine thousand, two hundred sixty-three".
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