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49886434121 is a prime number
BaseRepresentation
bin101110011101011101…
…101001001101001001
311202202200010102112012
4232131131221031021
51304131411342441
634530103225305
73414142456616
oct563535511511
9152680112465
1049886434121
111a17a656357
129802a48235
134920389594
1425b360b50d
15146e9109eb
hexb9d769349

49886434121 has 2 divisors, whose sum is σ = 49886434122. Its totient is φ = 49886434120.

The previous prime is 49886434007. The next prime is 49886434123. The reversal of 49886434121 is 12143468894.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 49845474121 + 40960000 = 223261^2 + 6400^2 .

It is a cyclic number.

It is not a de Polignac number, because 49886434121 - 210 = 49886433097 is a prime.

It is a Sophie Germain prime.

Together with 49886434123, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 49886434121.

It is not a weakly prime, because it can be changed into another prime (49886434123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24943217060 + 24943217061.

It is an arithmetic number, because the mean of its divisors is an integer number (24943217061).

Almost surely, 249886434121 is an apocalyptic number.

It is an amenable number.

49886434121 is a deficient number, since it is larger than the sum of its proper divisors (1).

49886434121 is an equidigital number, since it uses as much as digits as its factorization.

49886434121 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1327104, while the sum is 50.

The spelling of 49886434121 in words is "forty-nine billion, eight hundred eighty-six million, four hundred thirty-four thousand, one hundred twenty-one".