Base | Representation |
---|---|
bin | 10110101011111110010000… |
… | …10111010101101110110011 |
3 | 20112122101021112100202102201 |
4 | 23111333020113111232303 |
5 | 23014342001104021223 |
6 | 254034513235124031 |
7 | 13336251002054266 |
oct | 1325771027255663 |
9 | 215571245322381 |
10 | 49889406704563 |
11 | 14994a8451a378 |
12 | 5718a99443617 |
13 | 21ab7213370aa |
14 | c46935704cdd |
15 | 5b7b10920ead |
hex | 2d5fc85d5bb3 |
49889406704563 has 2 divisors, whose sum is σ = 49889406704564. Its totient is φ = 49889406704562.
The previous prime is 49889406704561. The next prime is 49889406704573. The reversal of 49889406704563 is 36540760498894.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 49889406704563 - 21 = 49889406704561 is a prime.
Together with 49889406704561, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (49889406704561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 24944703352281 + 24944703352282.
It is an arithmetic number, because the mean of its divisors is an integer number (24944703352282).
Almost surely, 249889406704563 is an apocalyptic number.
49889406704563 is a deficient number, since it is larger than the sum of its proper divisors (1).
49889406704563 is an equidigital number, since it uses as much as digits as its factorization.
49889406704563 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1254113280, while the sum is 73.
The spelling of 49889406704563 in words is "forty-nine trillion, eight hundred eighty-nine billion, four hundred six million, seven hundred four thousand, five hundred sixty-three".
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