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499012680433 is a prime number
BaseRepresentation
bin1110100001011110111…
…10010011101011110001
31202201001001101200102011
413100233132103223301
531133434221233213
61021124313322521
751023666540551
oct7205736235361
91681031350364
10499012680433
111826a2715713
1280866406441
1338097730507
141a21c057161
15cea910903d
hex742f793af1

499012680433 has 2 divisors, whose sum is σ = 499012680434. Its totient is φ = 499012680432.

The previous prime is 499012680421. The next prime is 499012680457. The reversal of 499012680433 is 334086210994.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 492225721744 + 6786958689 = 701588^2 + 82383^2 .

It is a cyclic number.

It is not a de Polignac number, because 499012680433 - 25 = 499012680401 is a prime.

It is not a weakly prime, because it can be changed into another prime (499012680473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249506340216 + 249506340217.

It is an arithmetic number, because the mean of its divisors is an integer number (249506340217).

Almost surely, 2499012680433 is an apocalyptic number.

It is an amenable number.

499012680433 is a deficient number, since it is larger than the sum of its proper divisors (1).

499012680433 is an equidigital number, since it uses as much as digits as its factorization.

499012680433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1119744, while the sum is 49.

The spelling of 499012680433 in words is "four hundred ninety-nine billion, twelve million, six hundred eighty thousand, four hundred thirty-three".