Base | Representation |
---|---|
bin | 1110100001011110111… |
… | …10010011101100011001 |
3 | 1202201001001101200110122 |
4 | 13100233132103230121 |
5 | 31133434221233343 |
6 | 1021124313323025 |
7 | 51023666540636 |
oct | 7205736235431 |
9 | 1681031350418 |
10 | 499012680473 |
11 | 1826a271574a |
12 | 80866406475 |
13 | 38097730538 |
14 | 1a21c05718d |
15 | cea9109068 |
hex | 742f793b19 |
499012680473 has 2 divisors, whose sum is σ = 499012680474. Its totient is φ = 499012680472.
The previous prime is 499012680469. The next prime is 499012680503. The reversal of 499012680473 is 374086210994.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 383801313289 + 115211367184 = 619517^2 + 339428^2 .
It is a cyclic number.
It is not a de Polignac number, because 499012680473 - 22 = 499012680469 is a prime.
It is not a weakly prime, because it can be changed into another prime (499012680433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249506340236 + 249506340237.
It is an arithmetic number, because the mean of its divisors is an integer number (249506340237).
Almost surely, 2499012680473 is an apocalyptic number.
It is an amenable number.
499012680473 is a deficient number, since it is larger than the sum of its proper divisors (1).
499012680473 is an equidigital number, since it uses as much as digits as its factorization.
499012680473 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2612736, while the sum is 53.
The spelling of 499012680473 in words is "four hundred ninety-nine billion, twelve million, six hundred eighty thousand, four hundred seventy-three".
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