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4995049816693 is a prime number
BaseRepresentation
bin100100010110000000000…
…1010111000001001110101
3122200112002121110202111201
41020230000022320021311
51123314330223113233
614342405540532501
71023610663616626
oct110540012701165
918615077422451
104995049816693
111656430445582
126880a80b1131
132a3053658511
14133a94171a4d
1589decd5a77d
hex48b002b8275

4995049816693 has 2 divisors, whose sum is σ = 4995049816694. Its totient is φ = 4995049816692.

The previous prime is 4995049816639. The next prime is 4995049816699. The reversal of 4995049816693 is 3966189405994.

Together with previous prime (4995049816639) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4954617454609 + 40432362084 = 2225897^2 + 201078^2 .

It is a cyclic number.

It is not a de Polignac number, because 4995049816693 - 229 = 4994512945781 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (4995049816699) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2497524908346 + 2497524908347.

It is an arithmetic number, because the mean of its divisors is an integer number (2497524908347).

Almost surely, 24995049816693 is an apocalyptic number.

It is an amenable number.

4995049816693 is a deficient number, since it is larger than the sum of its proper divisors (1).

4995049816693 is an equidigital number, since it uses as much as digits as its factorization.

4995049816693 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 453496320, while the sum is 73.

The spelling of 4995049816693 in words is "four trillion, nine hundred ninety-five billion, forty-nine million, eight hundred sixteen thousand, six hundred ninety-three".