Base | Representation |
---|---|
bin | 100100010110101110110… |
… | …0011111001101110001011 |
3 | 122200200010210202112102221 |
4 | 1020231131203321232023 |
5 | 1123331032331022203 |
6 | 14343225231434511 |
7 | 1023664550553541 |
oct | 110553543715613 |
9 | 18620123675387 |
10 | 4996616657803 |
11 | 1657064929491 |
12 | 688464985a37 |
13 | 2a3243151534 |
14 | 133ba22b3d91 |
15 | 89e906a9abd |
hex | 48b5d8f9b8b |
4996616657803 has 2 divisors, whose sum is σ = 4996616657804. Its totient is φ = 4996616657802.
The previous prime is 4996616657801. The next prime is 4996616657807. The reversal of 4996616657803 is 3087566166994.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 4996616657803 - 21 = 4996616657801 is a prime.
Together with 4996616657801, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (4996616657801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2498308328901 + 2498308328902.
It is an arithmetic number, because the mean of its divisors is an integer number (2498308328902).
Almost surely, 24996616657803 is an apocalyptic number.
4996616657803 is a deficient number, since it is larger than the sum of its proper divisors (1).
4996616657803 is an equidigital number, since it uses as much as digits as its factorization.
4996616657803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 352719360, while the sum is 70.
The spelling of 4996616657803 in words is "four trillion, nine hundred ninety-six billion, six hundred sixteen million, six hundred fifty-seven thousand, eight hundred three".
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