Base | Representation |
---|---|
bin | 10110101111000010111100… |
… | …01101110011000100000011 |
3 | 20120000110211111202222122020 |
4 | 23113201132031303010003 |
5 | 23023104230000011041 |
6 | 254155215210012523 |
7 | 13350006464215650 |
oct | 1327413615630403 |
9 | 216013744688566 |
10 | 49995000000771 |
11 | 14a25840151721 |
12 | 5735448417143 |
13 | 21b867b894857 |
14 | c4bab1546c27 |
15 | 5ba740c08866 |
hex | 2d785e373103 |
49995000000771 has 64 divisors (see below), whose sum is σ = 78979356426240. Its totient is φ = 27539283957120.
The previous prime is 49995000000719. The next prime is 49995000000811. The reversal of 49995000000771 is 17700000059994.
It is a happy number.
49995000000771 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 49995000000771 - 29 = 49995000000259 is a prime.
It is not an unprimeable number, because it can be changed into a prime (49995000000271) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 119502126 + ... + 119919756.
It is an arithmetic number, because the mean of its divisors is an integer number (1234052444160).
Almost surely, 249995000000771 is an apocalyptic number.
49995000000771 is a deficient number, since it is larger than the sum of its proper divisors (28984356425469).
49995000000771 is a wasteful number, since it uses less digits than its factorization.
49995000000771 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 419576.
The product of its (nonzero) digits is 714420, while the sum is 51.
The spelling of 49995000000771 in words is "forty-nine trillion, nine hundred ninety-five billion, seven hundred seventy-one", and thus it is an aban number.
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