Base | Representation |
---|---|
bin | 100100011000010010001… |
… | …1011100101010111111101 |
3 | 122200222202022221120002121 |
4 | 1020300210123211113331 |
5 | 1123404401001041133 |
6 | 14344540300122541 |
7 | 1024143333325513 |
oct | 110604433452775 |
9 | 18628668846077 |
10 | 4999953143293 |
11 | 1658517223409 |
12 | 689036236451 |
13 | 2a36554697c4 |
14 | 133ddb46a4b3 |
15 | 8a0d856802d |
hex | 48c246e55fd |
4999953143293 has 2 divisors, whose sum is σ = 4999953143294. Its totient is φ = 4999953143292.
The previous prime is 4999953143287. The next prime is 4999953143333. The reversal of 4999953143293 is 3923413599994.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4940208584964 + 59744558329 = 2222658^2 + 244427^2 .
It is a cyclic number.
It is not a de Polignac number, because 4999953143293 - 233 = 4991363208701 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (4999953143893) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2499976571646 + 2499976571647.
It is an arithmetic number, because the mean of its divisors is an integer number (2499976571647).
Almost surely, 24999953143293 is an apocalyptic number.
It is an amenable number.
4999953143293 is a deficient number, since it is larger than the sum of its proper divisors (1).
4999953143293 is an equidigital number, since it uses as much as digits as its factorization.
4999953143293 is an evil number, because the sum of its binary digits is even.
The product of its digits is 255091680, while the sum is 70.
The spelling of 4999953143293 in words is "four trillion, nine hundred ninety-nine billion, nine hundred fifty-three million, one hundred forty-three thousand, two hundred ninety-three".
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