Base | Representation |
---|---|
bin | 1110100011010100100… |
… | …10110000001000100111 |
3 | 1202210120211021122221122 |
4 | 13101222102300020213 |
5 | 31142444333210413 |
6 | 1021410244404155 |
7 | 51060311454104 |
oct | 7215222601047 |
9 | 1683524248848 |
10 | 499999506983 |
11 | 183059761049 |
12 | 80aa09a665b |
13 | 381c4007552 |
14 | 1a2b3135aab |
15 | d015a87108 |
hex | 746a4b0227 |
499999506983 has 2 divisors, whose sum is σ = 499999506984. Its totient is φ = 499999506982.
The previous prime is 499999506949. The next prime is 499999506989. The reversal of 499999506983 is 389605999994.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 499999506983 - 210 = 499999505959 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 499999506898 and 499999506907.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (499999506989) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 249999753491 + 249999753492.
It is an arithmetic number, because the mean of its divisors is an integer number (249999753492).
Almost surely, 2499999506983 is an apocalyptic number.
499999506983 is a deficient number, since it is larger than the sum of its proper divisors (1).
499999506983 is an equidigital number, since it uses as much as digits as its factorization.
499999506983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1530550080, while the sum is 80.
The spelling of 499999506983 in words is "four hundred ninety-nine billion, nine hundred ninety-nine million, five hundred six thousand, nine hundred eighty-three".
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