Base | Representation |
---|---|
bin | 101110100100001110… |
… | …110111010101010101 |
3 | 11210001120211012002111 |
4 | 232210032313111111 |
5 | 1304400000002331 |
6 | 34545241311021 |
7 | 3420021663514 |
oct | 564416672525 |
9 | 153046735074 |
10 | 50000000341 |
11 | 1a228773335 |
12 | 9834a95471 |
13 | 493aa6cc25 |
14 | 25c473067b |
15 | 1479894db1 |
hex | ba43b7555 |
50000000341 has 2 divisors, whose sum is σ = 50000000342. Its totient is φ = 50000000340.
The previous prime is 50000000333. The next prime is 50000000359. The reversal of 50000000341 is 14300000005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 49931690116 + 68310225 = 223454^2 + 8265^2 .
It is a cyclic number.
It is not a de Polignac number, because 50000000341 - 23 = 50000000333 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50000003341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25000000170 + 25000000171.
It is an arithmetic number, because the mean of its divisors is an integer number (25000000171).
Almost surely, 250000000341 is an apocalyptic number.
It is an amenable number.
50000000341 is a deficient number, since it is larger than the sum of its proper divisors (1).
50000000341 is an equidigital number, since it uses as much as digits as its factorization.
50000000341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60, while the sum is 13.
Adding to 50000000341 its reverse (14300000005), we get a palindrome (64300000346).
The spelling of 50000000341 in words is "fifty billion, three hundred forty-one", and thus it is an aban number.
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