Base | Representation |
---|---|
bin | 101110100100011000… |
… | …010000111111001001 |
3 | 11210001202110101120112 |
4 | 232210120100333021 |
5 | 1304401112332323 |
6 | 34545410204105 |
7 | 3420051636335 |
oct | 564430207711 |
9 | 153052411515 |
10 | 50002464713 |
11 | 1a22a0a6903 |
12 | 9835883635 |
13 | 493b423836 |
14 | 25c4bb27c5 |
15 | 1479bd0178 |
hex | ba4610fc9 |
50002464713 has 2 divisors, whose sum is σ = 50002464714. Its totient is φ = 50002464712.
The previous prime is 50002464679. The next prime is 50002464727. The reversal of 50002464713 is 31746420005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 41839884304 + 8162580409 = 204548^2 + 90347^2 .
It is a cyclic number.
It is not a de Polignac number, because 50002464713 - 26 = 50002464649 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 50002464713.
It is not a weakly prime, because it can be changed into another prime (50002464313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25001232356 + 25001232357.
It is an arithmetic number, because the mean of its divisors is an integer number (25001232357).
Almost surely, 250002464713 is an apocalyptic number.
It is an amenable number.
50002464713 is a deficient number, since it is larger than the sum of its proper divisors (1).
50002464713 is an equidigital number, since it uses as much as digits as its factorization.
50002464713 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20160, while the sum is 32.
Adding to 50002464713 its reverse (31746420005), we get a palindrome (81748884718).
The spelling of 50002464713 in words is "fifty billion, two million, four hundred sixty-four thousand, seven hundred thirteen".
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