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50002990493 is a prime number
BaseRepresentation
bin101110100100011010…
…010001010110011101
311210001210110002210212
4232210122101112131
51304401231143433
634545425342205
73420056256251
oct564432212635
9153053402725
1050002990493
111a22a425935
129835a97965
13493b578c51
1425c4cac261
151479c85d48
hexba469159d

50002990493 has 2 divisors, whose sum is σ = 50002990494. Its totient is φ = 50002990492.

The previous prime is 50002990469. The next prime is 50002990507. The reversal of 50002990493 is 39409920005.

50002990493 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 47505689764 + 2497300729 = 217958^2 + 49973^2 .

It is a cyclic number.

It is not a de Polignac number, because 50002990493 - 232 = 45708023197 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 50002990493.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (50002990463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25001495246 + 25001495247.

It is an arithmetic number, because the mean of its divisors is an integer number (25001495247).

Almost surely, 250002990493 is an apocalyptic number.

It is an amenable number.

50002990493 is a deficient number, since it is larger than the sum of its proper divisors (1).

50002990493 is an equidigital number, since it uses as much as digits as its factorization.

50002990493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 87480, while the sum is 41.

The spelling of 50002990493 in words is "fifty billion, two million, nine hundred ninety thousand, four hundred ninety-three".