Base | Representation |
---|---|
bin | 10110101111010001111111… |
… | …01000011000111011001101 |
3 | 20120001020200101201112102010 |
4 | 23113220333220120323031 |
5 | 23023222300130444433 |
6 | 254203032452051433 |
7 | 13350413600043000 |
oct | 1327507750307315 |
9 | 216036611645363 |
10 | 50003076812493 |
11 | 14a29205312932 |
12 | 5736b21303b79 |
13 | 21b9367cbca9c |
14 | c4c23a0c7537 |
15 | 5baa64d27e63 |
hex | 2d7a3fa18ecd |
50003076812493 has 64 divisors (see below), whose sum is σ = 81948780864000. Its totient is φ = 27067377093120.
The previous prime is 50003076812483. The next prime is 50003076812501. The reversal of 50003076812493 is 39421867030005.
It is not a de Polignac number, because 50003076812493 - 29 = 50003076811981 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (50003076812443) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 14226448 + ... + 17389593.
It is an arithmetic number, because the mean of its divisors is an integer number (1280449701000).
It is a 1-persistent number, because it is pandigital, but 2⋅50003076812493 = 100006153624986 is not.
Almost surely, 250003076812493 is an apocalyptic number.
50003076812493 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
It is an amenable number.
50003076812493 is a deficient number, since it is larger than the sum of its proper divisors (31945704051507).
50003076812493 is a wasteful number, since it uses less digits than its factorization.
50003076812493 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 31616147 (or 31616133 counting only the distinct ones).
The product of its (nonzero) digits is 1088640, while the sum is 48.
The spelling of 50003076812493 in words is "fifty trillion, three billion, seventy-six million, eight hundred twelve thousand, four hundred ninety-three".
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