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500050555033 is a prime number
BaseRepresentation
bin1110100011011010101…
…01011111000010011001
31202210201101100011201011
413101231111133002121
531143100420230113
61021415310453521
751061501405201
oct7215525370231
91683641304634
10500050555033
11183085558217
1280ab5b042a1
133820176b9b3
141a2b9c23401
15d01a2bc63d
hex746d55f099

500050555033 has 2 divisors, whose sum is σ = 500050555034. Its totient is φ = 500050555032.

The previous prime is 500050555031. The next prime is 500050555051. The reversal of 500050555033 is 330555050005.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 292585791744 + 207464763289 = 540912^2 + 455483^2 .

It is a cyclic number.

It is not a de Polignac number, because 500050555033 - 21 = 500050555031 is a prime.

It is a super-2 number, since 2×5000505550332 (a number of 24 digits) contains 22 as substring.

Together with 500050555031, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 500050554986 and 500050555004.

It is not a weakly prime, because it can be changed into another prime (500050555031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250025277516 + 250025277517.

It is an arithmetic number, because the mean of its divisors is an integer number (250025277517).

Almost surely, 2500050555033 is an apocalyptic number.

It is an amenable number.

500050555033 is a deficient number, since it is larger than the sum of its proper divisors (1).

500050555033 is an equidigital number, since it uses as much as digits as its factorization.

500050555033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28125, while the sum is 31.

The spelling of 500050555033 in words is "five hundred billion, fifty million, five hundred fifty-five thousand, thirty-three".