Base | Representation |
---|---|
bin | 101110100100100111… |
… | …011000111000110001 |
3 | 11210002000220210212121 |
4 | 232210213120320301 |
5 | 1304403121213413 |
6 | 34550031154241 |
7 | 3420130430605 |
oct | 564447307061 |
9 | 153060823777 |
10 | 50006429233 |
11 | 1a231364472 |
12 | 9837075981 |
13 | 493c1b11c7 |
14 | 25c5525505 |
15 | 147a214b8d |
hex | ba49d8e31 |
50006429233 has 2 divisors, whose sum is σ = 50006429234. Its totient is φ = 50006429232.
The previous prime is 50006429227. The next prime is 50006429273. The reversal of 50006429233 is 33292460005.
50006429233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43333499889 + 6672929344 = 208167^2 + 81688^2 .
It is a cyclic number.
It is not a de Polignac number, because 50006429233 - 25 = 50006429201 is a prime.
It is not a weakly prime, because it can be changed into another prime (50006429273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25003214616 + 25003214617.
It is an arithmetic number, because the mean of its divisors is an integer number (25003214617).
Almost surely, 250006429233 is an apocalyptic number.
It is an amenable number.
50006429233 is a deficient number, since it is larger than the sum of its proper divisors (1).
50006429233 is an equidigital number, since it uses as much as digits as its factorization.
50006429233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38880, while the sum is 34.
Adding to 50006429233 its reverse (33292460005), we get a palindrome (83298889238).
The spelling of 50006429233 in words is "fifty billion, six million, four hundred twenty-nine thousand, two hundred thirty-three".
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