Base | Representation |
---|---|
bin | 10110101111100101000010… |
… | …11011000101110010010101 |
3 | 20120002020002101102122112011 |
4 | 23113302201123011302111 |
5 | 23023404223200143424 |
6 | 254211443553424221 |
7 | 13351225244613223 |
oct | 1327624133056225 |
9 | 216066071378464 |
10 | 50013307427989 |
11 | 14a32585220764 |
12 | 5738ab756b071 |
13 | 21ba3086c3719 |
14 | c4c92ab1bb13 |
15 | 5bae6308b694 |
hex | 2d7ca16c5c95 |
50013307427989 has 2 divisors, whose sum is σ = 50013307427990. Its totient is φ = 50013307427988.
The previous prime is 50013307427983. The next prime is 50013307428131. The reversal of 50013307427989 is 98972470331005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 36396690823089 + 13616616604900 = 6032967^2 + 3690070^2 .
It is a cyclic number.
It is not a de Polignac number, because 50013307427989 - 29 = 50013307427477 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50013307427983) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25006653713994 + 25006653713995.
It is an arithmetic number, because the mean of its divisors is an integer number (25006653713995).
Almost surely, 250013307427989 is an apocalyptic number.
It is an amenable number.
50013307427989 is a deficient number, since it is larger than the sum of its proper divisors (1).
50013307427989 is an equidigital number, since it uses as much as digits as its factorization.
50013307427989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11430720, while the sum is 58.
The spelling of 50013307427989 in words is "fifty trillion, thirteen billion, three hundred seven million, four hundred twenty-seven thousand, nine hundred eighty-nine".
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