Base | Representation |
---|---|
bin | 1110100011100101010… |
… | …10000010110000101101 |
3 | 1202210221121022211101011 |
4 | 13101302222002300231 |
5 | 31143241244032232 |
6 | 1021432220145221 |
7 | 51063634262041 |
oct | 7216252026055 |
9 | 1683847284334 |
10 | 500139830317 |
11 | 183120994046 |
12 | 80b1b998211 |
13 | 382170c8aca |
14 | 1a2c7a22021 |
15 | d023054547 |
hex | 7472a82c2d |
500139830317 has 2 divisors, whose sum is σ = 500139830318. Its totient is φ = 500139830316.
The previous prime is 500139830287. The next prime is 500139830401. The reversal of 500139830317 is 713038931005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 269964415561 + 230175414756 = 519581^2 + 479766^2 .
It is a cyclic number.
It is not a de Polignac number, because 500139830317 - 223 = 500131441709 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 500139830317.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (500139834317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250069915158 + 250069915159.
It is an arithmetic number, because the mean of its divisors is an integer number (250069915159).
Almost surely, 2500139830317 is an apocalyptic number.
It is an amenable number.
500139830317 is a deficient number, since it is larger than the sum of its proper divisors (1).
500139830317 is an equidigital number, since it uses as much as digits as its factorization.
500139830317 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 68040, while the sum is 40.
The spelling of 500139830317 in words is "five hundred billion, one hundred thirty-nine million, eight hundred thirty thousand, three hundred seventeen".
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