Base | Representation |
---|---|
bin | 111000110111101111011011… |
… | …0110100011001011010100111 |
3 | 2102121012200120020111000201022 |
4 | 1301233132312310121122213 |
5 | 1011031432012444340234 |
6 | 4531532032351121355 |
7 | 210240210062501621 |
oct | 16157366664313247 |
9 | 2377180506430638 |
10 | 500242203121319 |
11 | 13543558841372a |
12 | 4813235981325b |
13 | 1861883931a6a9 |
14 | 8b75bcd559c11 |
15 | 3cc76aae90e2e |
hex | 1c6f7b6d196a7 |
500242203121319 has 2 divisors, whose sum is σ = 500242203121320. Its totient is φ = 500242203121318.
The previous prime is 500242203121313. The next prime is 500242203121351. The reversal of 500242203121319 is 913121302242005.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-500242203121319 is a prime.
It is a super-2 number, since 2×5002422031213192 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (500242203121313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250121101560659 + 250121101560660.
It is an arithmetic number, because the mean of its divisors is an integer number (250121101560660).
Almost surely, 2500242203121319 is an apocalyptic number.
500242203121319 is a deficient number, since it is larger than the sum of its proper divisors (1).
500242203121319 is an equidigital number, since it uses as much as digits as its factorization.
500242203121319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25920, while the sum is 35.
The spelling of 500242203121319 in words is "five hundred trillion, two hundred forty-two billion, two hundred three million, one hundred twenty-one thousand, three hundred nineteen".
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