Base | Representation |
---|---|
bin | 100100011001011111000… |
… | …0100101100010010100111 |
3 | 122201020101222022210102001 |
4 | 1020302332010230102213 |
5 | 1123430140343133300 |
6 | 14350044141030131 |
7 | 1024264243330522 |
oct | 110627604542247 |
9 | 18636358283361 |
10 | 5002530833575 |
11 | 165961a270260 |
12 | 689635555347 |
13 | 2a39764cac22 |
14 | 1341a3941bb9 |
15 | 8a1d99dd16a |
hex | 48cbe12c4a7 |
5002530833575 has 24 divisors (see below), whose sum is σ = 6770239199280. Its totient is φ = 3636494937600.
The previous prime is 5002530833567. The next prime is 5002530833617. The reversal of 5002530833575 is 5753380352005.
It is not a de Polignac number, because 5002530833575 - 23 = 5002530833567 is a prime.
It is a super-3 number, since 3×50025308335753 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 3686724 + ... + 4857673.
It is an arithmetic number, because the mean of its divisors is an integer number (282093299970).
Almost surely, 25002530833575 is an apocalyptic number.
5002530833575 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
5002530833575 is a deficient number, since it is larger than the sum of its proper divisors (1767708365705).
5002530833575 is a wasteful number, since it uses less digits than its factorization.
5002530833575 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8546547 (or 8546542 counting only the distinct ones).
The product of its (nonzero) digits is 1890000, while the sum is 46.
The spelling of 5002530833575 in words is "five trillion, two billion, five hundred thirty million, eight hundred thirty-three thousand, five hundred seventy-five".
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