Base | Representation |
---|---|
bin | 10110110000010111110001… |
… | …10110110101110011000101 |
3 | 20120011211101120002011120211 |
4 | 23120023320312311303011 |
5 | 23024331013243432401 |
6 | 254232150354355421 |
7 | 13353211221661426 |
oct | 1330137066656305 |
9 | 216154346064524 |
10 | 50040544124101 |
11 | 14a43091670673 |
12 | 5742238b8bb71 |
13 | 21bca5943935b |
14 | c4dd9217564d |
15 | 5bba092c8951 |
hex | 2d82f8db5cc5 |
50040544124101 has 2 divisors, whose sum is σ = 50040544124102. Its totient is φ = 50040544124100.
The previous prime is 50040544123993. The next prime is 50040544124119. The reversal of 50040544124101 is 10142144504005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32685529699876 + 17355014424225 = 5717126^2 + 4165935^2 .
It is a cyclic number.
It is not a de Polignac number, because 50040544124101 - 29 = 50040544123589 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50040544124161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25020272062050 + 25020272062051.
It is an arithmetic number, because the mean of its divisors is an integer number (25020272062051).
Almost surely, 250040544124101 is an apocalyptic number.
It is an amenable number.
50040544124101 is a deficient number, since it is larger than the sum of its proper divisors (1).
50040544124101 is an equidigital number, since it uses as much as digits as its factorization.
50040544124101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12800, while the sum is 31.
Adding to 50040544124101 its reverse (10142144504005), we get a palindrome (60182688628106).
The spelling of 50040544124101 in words is "fifty trillion, forty billion, five hundred forty-four million, one hundred twenty-four thousand, one hundred one".
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