Base | Representation |
---|---|
bin | 100100011010010110110… |
… | …0110101101100001000111 |
3 | 122201102020101022001000111 |
4 | 1020310231212231201013 |
5 | 1123443003404204341 |
6 | 14350553543053451 |
7 | 1024361514222655 |
oct | 110645546554107 |
9 | 18642211261014 |
10 | 5004402022471 |
11 | 165a39a528165 |
12 | 689a78141287 |
13 | 2a3bb40849a7 |
14 | 134300269dd5 |
15 | 8a298e09681 |
hex | 48d2d9ad847 |
5004402022471 has 2 divisors, whose sum is σ = 5004402022472. Its totient is φ = 5004402022470.
The previous prime is 5004402022463. The next prime is 5004402022531. The reversal of 5004402022471 is 1742202044005.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5004402022471 - 23 = 5004402022463 is a prime.
It is a super-3 number, since 3×50044020224713 (a number of 39 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5004402026471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2502201011235 + 2502201011236.
It is an arithmetic number, because the mean of its divisors is an integer number (2502201011236).
Almost surely, 25004402022471 is an apocalyptic number.
5004402022471 is a deficient number, since it is larger than the sum of its proper divisors (1).
5004402022471 is an equidigital number, since it uses as much as digits as its factorization.
5004402022471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17920, while the sum is 31.
Adding to 5004402022471 its reverse (1742202044005), we get a palindrome (6746604066476).
The spelling of 5004402022471 in words is "five trillion, four billion, four hundred two million, twenty-two thousand, four hundred seventy-one".
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