Base | Representation |
---|---|
bin | 10110110000101001011110… |
… | …11100101001101000101101 |
3 | 20120012201221000221122120211 |
4 | 23120110233130221220231 |
5 | 23030010000241040023 |
6 | 254240401525142421 |
7 | 13353665616041434 |
oct | 1330245734515055 |
9 | 216181830848524 |
10 | 50050049940013 |
11 | 14a4711a430882 |
12 | 574405055aa11 |
13 | 21c09129299b6 |
14 | c5061481811b |
15 | 5bbdb3abba0d |
hex | 2d852f729a2d |
50050049940013 has 2 divisors, whose sum is σ = 50050049940014. Its totient is φ = 50050049940012.
The previous prime is 50050049939983. The next prime is 50050049940029. The reversal of 50050049940013 is 31004994005005.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 32222629544004 + 17827420396009 = 5676498^2 + 4222253^2 .
It is a cyclic number.
It is not a de Polignac number, because 50050049940013 - 29 = 50050049939501 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50050049940043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25025024970006 + 25025024970007.
It is an arithmetic number, because the mean of its divisors is an integer number (25025024970007).
Almost surely, 250050049940013 is an apocalyptic number.
It is an amenable number.
50050049940013 is a deficient number, since it is larger than the sum of its proper divisors (1).
50050049940013 is an equidigital number, since it uses as much as digits as its factorization.
50050049940013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 50050049940013 in words is "fifty trillion, fifty billion, forty-nine million, nine hundred forty thousand, thirteen".
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