Base | Representation |
---|---|
bin | 10110110000101011010001… |
… | …01010111111100001011111 |
3 | 20120012211101221110210122211 |
4 | 23120111220222333201133 |
5 | 23030013432030012431 |
6 | 254241041102421251 |
7 | 13354031454320146 |
oct | 1330255052774137 |
9 | 216184357423584 |
10 | 50051010000991 |
11 | 14a475723558aa |
12 | 5744279b91827 |
13 | 21c0a367c200c |
14 | c506a612a75d |
15 | 5bbe1d00e2b1 |
hex | 2d8568abf85f |
50051010000991 has 2 divisors, whose sum is σ = 50051010000992. Its totient is φ = 50051010000990.
The previous prime is 50051010000881. The next prime is 50051010001021. The reversal of 50051010000991 is 19900001015005.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50051010000991 - 211 = 50051009998943 is a prime.
It is a super-2 number, since 2×500510100009912 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (50051010070991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25025505000495 + 25025505000496.
It is an arithmetic number, because the mean of its divisors is an integer number (25025505000496).
Almost surely, 250051010000991 is an apocalyptic number.
50051010000991 is a deficient number, since it is larger than the sum of its proper divisors (1).
50051010000991 is an equidigital number, since it uses as much as digits as its factorization.
50051010000991 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2025, while the sum is 31.
Adding to 50051010000991 its reverse (19900001015005), we get a palindrome (69951011015996).
The spelling of 50051010000991 in words is "fifty trillion, fifty-one billion, ten million, nine hundred ninety-one", and thus it is an aban number.
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