Search a number
-
+
5005253433121 is a prime number
BaseRepresentation
bin100100011010110000001…
…0110100101011100100001
3122201111102201101011212021
41020311200112211130201
51124001224334324441
614351214235501441
71024421563130524
oct110654026453441
918644381334767
105005253433121
11165a797092627
1268a0752b7881
132a3cbb598086
14134381378bbb
158a2e8a393d1
hex48d605a5721

5005253433121 has 2 divisors, whose sum is σ = 5005253433122. Its totient is φ = 5005253433120.

The previous prime is 5005253433067. The next prime is 5005253433137. The reversal of 5005253433121 is 1213343525005.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3017999343121 + 1987254090000 = 1737239^2 + 1409700^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5005253433121 is a prime.

It is not a weakly prime, because it can be changed into another prime (5005253431121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2502626716560 + 2502626716561.

It is an arithmetic number, because the mean of its divisors is an integer number (2502626716561).

Almost surely, 25005253433121 is an apocalyptic number.

It is an amenable number.

5005253433121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5005253433121 is an equidigital number, since it uses as much as digits as its factorization.

5005253433121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 5005253433121 its reverse (1213343525005), we get a palindrome (6218596958126).

The spelling of 5005253433121 in words is "five trillion, five billion, two hundred fifty-three million, four hundred thirty-three thousand, one hundred twenty-one".