Base | Representation |
---|---|
bin | 100100011011001100011… |
… | …0110101010001110111001 |
3 | 122201120212210002010112102 |
4 | 1020312120312222032321 |
5 | 1124010200022143213 |
6 | 14351452301153145 |
7 | 1024454223332552 |
oct | 110663066521671 |
9 | 18646783063472 |
10 | 5006201365433 |
11 | 1660133183164 |
12 | 68a29a85b7b5 |
13 | 2a410caa4978 |
14 | 134431211329 |
15 | 8a351d83158 |
hex | 48d98daa3b9 |
5006201365433 has 2 divisors, whose sum is σ = 5006201365434. Its totient is φ = 5006201365432.
The previous prime is 5006201365427. The next prime is 5006201365493. The reversal of 5006201365433 is 3345631026005.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5006195927209 + 5438224 = 2237453^2 + 2332^2 .
It is a cyclic number.
It is not a de Polignac number, because 5006201365433 - 224 = 5006184588217 is a prime.
It is a super-2 number, since 2×50062013654332 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5006201365493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2503100682716 + 2503100682717.
It is an arithmetic number, because the mean of its divisors is an integer number (2503100682717).
Almost surely, 25006201365433 is an apocalyptic number.
It is an amenable number.
5006201365433 is a deficient number, since it is larger than the sum of its proper divisors (1).
5006201365433 is an equidigital number, since it uses as much as digits as its factorization.
5006201365433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 194400, while the sum is 38.
The spelling of 5006201365433 in words is "five trillion, six billion, two hundred one million, three hundred sixty-five thousand, four hundred thirty-three".
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