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5010062757433 is a prime number
BaseRepresentation
bin100100011100111111100…
…0000101100111000111001
3122201221211212222011112221
41020321333000230320321
51124041102031214213
614353331400204041
71024652011534306
oct110717700547071
918657755864487
105010062757433
1116618348a6118
1268ab97a69621
132a45a6a857c6
141346b9da40ad
158a4cad7938d
hex48e7f02ce39

5010062757433 has 2 divisors, whose sum is σ = 5010062757434. Its totient is φ = 5010062757432.

The previous prime is 5010062757319. The next prime is 5010062757449. The reversal of 5010062757433 is 3347572600105.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3949269874729 + 1060792882704 = 1987277^2 + 1029948^2 .

It is a cyclic number.

It is not a de Polignac number, because 5010062757433 - 29 = 5010062756921 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5010062757433.

It is not a weakly prime, because it can be changed into another prime (5010062157433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505031378716 + 2505031378717.

It is an arithmetic number, because the mean of its divisors is an integer number (2505031378717).

Almost surely, 25010062757433 is an apocalyptic number.

It is an amenable number.

5010062757433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5010062757433 is an equidigital number, since it uses as much as digits as its factorization.

5010062757433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 529200, while the sum is 43.

The spelling of 5010062757433 in words is "five trillion, ten billion, sixty-two million, seven hundred fifty-seven thousand, four hundred thirty-three".