Base | Representation |
---|---|
bin | 1001010101010001… |
… | …00001011111000001 |
3 | 110221011122012222121 |
4 | 10222220201133001 |
5 | 40230104431111 |
6 | 2145054404241 |
7 | 235105165054 |
oct | 45250413701 |
9 | 13834565877 |
10 | 5010233281 |
11 | 2141167469 |
12 | b79b00681 |
13 | 61b0026a1 |
14 | 3575a6a9b |
15 | 1e4cc8871 |
hex | 12aa217c1 |
5010233281 has 2 divisors, whose sum is σ = 5010233282. Its totient is φ = 5010233280.
The previous prime is 5010233243. The next prime is 5010233321. The reversal of 5010233281 is 1823320105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3851443600 + 1158789681 = 62060^2 + 34041^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5010233281 is a prime.
It is a super-2 number, since 2×50102332812 = 50204875060080049922, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5010213281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505116640 + 2505116641.
It is an arithmetic number, because the mean of its divisors is an integer number (2505116641).
Almost surely, 25010233281 is an apocalyptic number.
It is an amenable number.
5010233281 is a deficient number, since it is larger than the sum of its proper divisors (1).
5010233281 is an equidigital number, since it uses as much as digits as its factorization.
5010233281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 5010233281 is about 70783.0013562578. The cubic root of 5010233281 is about 1711.1417293436.
Adding to 5010233281 its reverse (1823320105), we get a palindrome (6833553386).
The spelling of 5010233281 in words is "five billion, ten million, two hundred thirty-three thousand, two hundred eighty-one".
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