501025540133 has 2 divisors, whose sum is σ = 501025540134. Its totient is φ = 501025540132.

The previous prime is 501025540129. The next prime is 501025540163. The reversal of 501025540133 is 331045520105.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 473649521284 + 27376018849 = 688222^2 + 165457^2 .

It is a cyclic number.

It is not a de Polignac number, because 501025540133 - 2² = 501025540129 is a prime.

It is a super-3 number, since 3×501025540133³ (a number of 36 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 501025540096 and 501025540105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (501025540163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 250512770066 + 250512770067.

It is an arithmetic number, because the mean of its divisors is an integer number (250512770067).

Almost surely, 2^501025540133 is an apocalyptic number.

It is an amenable number.

501025540133 is a deficient number, since it is larger than the sum of its proper divisors (1).

501025540133 is an equidigital number, since it uses as much as digits as its factorization.

501025540133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9000, while the sum is 29.

The spelling of 501025540133 in words is "five hundred one billion, twenty-five million, five hundred forty thousand, one hundred thirty-three".