Base | Representation |
---|---|
bin | 10110110010010000110010… |
… | …01100001110100101101001 |
3 | 20120102001002012221001110102 |
4 | 23121020121030032211221 |
5 | 23031412041321023032 |
6 | 254322053134355145 |
7 | 13361001163155515 |
oct | 1331103114164551 |
9 | 216361065831412 |
10 | 50105511111017 |
11 | 14a6869a85749a |
12 | 575294a35bab5 |
13 | 21c5c10c3684b |
14 | c53196575145 |
15 | 5bd55cb11362 |
hex | 2d921930e969 |
50105511111017 has 2 divisors, whose sum is σ = 50105511111018. Its totient is φ = 50105511111016.
The previous prime is 50105511111013. The next prime is 50105511111059. The reversal of 50105511111017 is 71011111550105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 42550951025881 + 7554560085136 = 6523109^2 + 2748556^2 .
It is a cyclic number.
It is not a de Polignac number, because 50105511111017 - 22 = 50105511111013 is a prime.
It is not a weakly prime, because it can be changed into another prime (50105511111013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25052755555508 + 25052755555509.
It is an arithmetic number, because the mean of its divisors is an integer number (25052755555509).
Almost surely, 250105511111017 is an apocalyptic number.
It is an amenable number.
50105511111017 is a deficient number, since it is larger than the sum of its proper divisors (1).
50105511111017 is an equidigital number, since it uses as much as digits as its factorization.
50105511111017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 875, while the sum is 29.
The spelling of 50105511111017 in words is "fifty trillion, one hundred five billion, five hundred eleven million, one hundred eleven thousand, seventeen".
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