Base | Representation |
---|---|
bin | 101110101010111000… |
… | …001010101001010011 |
3 | 11210100100121111000221 |
4 | 232222320022221103 |
5 | 1310112020200033 |
6 | 35004303053511 |
7 | 3422544433234 |
oct | 565270125123 |
9 | 153310544027 |
10 | 50111490643 |
11 | 1a2856a2685 |
12 | 98662a1297 |
13 | 4957ba7716 |
14 | 25d547308b |
15 | 148456912d |
hex | baae0aa53 |
50111490643 has 2 divisors, whose sum is σ = 50111490644. Its totient is φ = 50111490642.
The previous prime is 50111490613. The next prime is 50111490659. The reversal of 50111490643 is 34609411105.
50111490643 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 50111490643 - 213 = 50111482451 is a prime.
It is a super-2 number, since 2×501114906432 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 50111490599 and 50111490608.
It is not a weakly prime, because it can be changed into another prime (50111490613) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25055745321 + 25055745322.
It is an arithmetic number, because the mean of its divisors is an integer number (25055745322).
Almost surely, 250111490643 is an apocalyptic number.
50111490643 is a deficient number, since it is larger than the sum of its proper divisors (1).
50111490643 is an equidigital number, since it uses as much as digits as its factorization.
50111490643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 50111490643 in words is "fifty billion, one hundred eleven million, four hundred ninety thousand, six hundred forty-three".
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