Base | Representation |
---|---|
bin | 100100011101100010111… |
… | …1010111000001001001001 |
3 | 122202001220210111221012021 |
4 | 1020323011322320021021 |
5 | 1124101021104204001 |
6 | 14354045414444441 |
7 | 1025023335460012 |
oct | 110730572701111 |
9 | 18661823457167 |
10 | 5011252413001 |
11 | 1662295386a3a |
12 | 68b26a363721 |
13 | 2a4736397703 |
14 | 13478dda0009 |
15 | 8a54a51eba1 |
hex | 48ec5eb8249 |
5011252413001 has 2 divisors, whose sum is σ = 5011252413002. Its totient is φ = 5011252413000.
The previous prime is 5011252412977. The next prime is 5011252413029. The reversal of 5011252413001 is 1003142521105.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4791497724601 + 219754688400 = 2188949^2 + 468780^2 .
It is a cyclic number.
It is not a de Polignac number, because 5011252413001 - 233 = 5002662478409 is a prime.
It is a super-2 number, since 2×50112524130012 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5011255413001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2505626206500 + 2505626206501.
It is an arithmetic number, because the mean of its divisors is an integer number (2505626206501).
Almost surely, 25011252413001 is an apocalyptic number.
It is an amenable number.
5011252413001 is a deficient number, since it is larger than the sum of its proper divisors (1).
5011252413001 is an equidigital number, since it uses as much as digits as its factorization.
5011252413001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1200, while the sum is 25.
Adding to 5011252413001 its reverse (1003142521105), we get a palindrome (6014394934106).
The spelling of 5011252413001 in words is "five trillion, eleven billion, two hundred fifty-two million, four hundred thirteen thousand, one".
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